douxuan0698 2015-05-31 15:31
浏览 6

使用变量返回数据

$raw_data = array ('data' => array ('id' => 'foo'));
$fields = array ('id_source' => "data['id']"); 

foreach ($raw_data as $data) {
    foreach ($fields as $key => $path) {
        var_dump ($data['id']);
        var_dump ($$path);
    }
}

The first var_dump gives me the correct value of foo. However, the second one gives me Undefined variable: data['id']. Can anyone tell me why that would be the case, especially since the first var_dump worked confirming the variable $data['id'] is set.

I realized this example is basic and I could just do $data[$key] and change $fields = array ('id_source' => 'id'); but I want to be able to go deeper into the multidimensional arrays when needed. That is why I'm trying to do my original approach.

  • 写回答

0条回答 默认 最新

    报告相同问题?

    悬赏问题

    • ¥15 孟德尔随机化结果不一致
    • ¥20 求用stm32f103c6t6在lcd1206上显示Door is open和password:
    • ¥15 apm2.8飞控罗盘bad health,加速度计校准失败
    • ¥15 求解O-S方程的特征值问题给出边界层布拉休斯平行流的中性曲线
    • ¥15 谁有desed数据集呀
    • ¥20 手写数字识别运行c仿真时,程序报错错误代码sim211-100
    • ¥15 关于#hadoop#的问题
    • ¥15 (标签-Python|关键词-socket)
    • ¥15 keil里为什么main.c定义的函数在it.c调用不了
    • ¥50 切换TabTip键盘的输入法