PHP和正则表达式将字符串的两个独立部分提取为ONE重组变量

Question

I have a PHP string consisting of HTML code as follows:

$string =
'<ul>
<li>
<a href="/nalcrom">Nalcrom</a>
        (Sodium Cromoglicate)
</li>
<li>
<a href="/alimemazine">Alimemazine</a>
</li>
<li>
<a href="/xolair">Xolair</a>
        (Omalizumab)
</li>
</ul>';

using

preg_match_all($regex,$string,$matches, PREG_PATTERN_ORDER);

for ($i = 0; $i < count($matches[0]); ++$i)
{ echo $i . "    " . $matches[0][$i]. "<br>"; }

if I use

$regex = "^(?<=>).*?(?=(\Q</a>\E))^";

I get

1 Nalcrom

2 Alimemazine

3 Xolair

whereas if I use

$regex = "^\(.*?\)^";

I get

1 (Sodium Cromoglicate)

2 (Omalizumab)

Trying

$regex = "^(?<=>).*?(?=(\Q</a>\E))(\(.*?\))^";

and variations upon it I get nothing but blank, whereas what I need is:

1 Nalcrom (Sodium Cromoglicate)

2 Alimemazine

3 Xolair (Omalizumab)

Any ideas on how I can do this? thnx

Answer 1

Make the second regex group optional ?, i.e.:

   $string =
    '<ul>
    <li>
    <a href="/nalcrom">Nalcrom</a>
            (Sodium Cromoglicate)
    </li>
    <li>
    <a href="/alimemazine">Alimemazine</a>
    </li>
    <li>
    <a href="/xolair">Xolair</a>
            (Omalizumab)
    </li>
    </ul>';

    preg_match_all('%">(.*?)</a>\s+(\(.*?\))?%i', $string, $match, PREG_PATTERN_ORDER);
    for ($i = 0; $i < count($match[0]); $i++) {
        echo  $match[1][$i] . " ". $match[2][$i];
    }

---

Output:

Nalcrom (Sodium Cromoglicate)
Alimemazine 
Xolair (Omalizumab)

---

DEMO