如何计算仍然使用PHP？

Question

I'm using WordPress to display some posts in a table and I have a pagination along with this. The table contains a column named "Number" and a column for post title. My problem is that I don't know how to number every post when I'm on the next page because the number of post starts all over instead of the count where remained. How would I resolve this?

The count it doesn't start from where it should when I go to the next page. My code:

<?php 
require('wp-load.php');

if ( is_user_logged_in() ) {
    global $wp_query;
    $paged = (isset($_GET['pagina'])) ? $_GET['pagina'] : 1;
    $args = array(
        'posts_per_page' => 2,
        'paged' => $paged,
        'post_type' => 'post'
    );
    
    $the_query = new WP_Query( $args );
   
    echo '<table>';
    $count = $paged - 1;
    echo '<tr>
                <td width="100">Number</td>
                <td width="200">Title</td>
          <tr>';
    while ( $the_query->have_posts() ) {
        $the_query->the_post();
            $count++;   
            //var_dump($count); 
        echo '<tr>';
            echo '<td>'.$count .'</td>';
            echo '<td>'.the_title().'</td>';  
        echo '</tr>';
        }
    echo '</table>';
    
    $big = 999999999; // need an unlikely integer
    echo paginate_links( array(
                        'format'       => '?pagina=%#%',
                        'current' => max( 1, $paged ),
                        'total' => $the_query->max_num_pages,
                        'prev_next'    => True,
                        'prev_text'    => __('Previous'),
                        'next_text'    => __('Next'),
                    ) ); 
}
?>

</div>

Answer 1

$count = (($paged -1) * 2) + 1;

where "2" is the posts_per_page val.

EDIT: here is the whole code:

$count = (($paged -1) * 2) + 1;
echo '<tr>
            <td width="100">Number</td>
            <td width="200">Title</td>
      <tr>';
while ( $the_query->have_posts() ) {
    $the_query->the_post();
    echo '<tr>';
    echo '<td>'.$count .'</td>';
    echo '<td>'.the_title().'</td>';  
    echo '</tr>';
    $count++;   
    }