Foreach循环 - 1-30作为列表，并在随机（1,2,4）次出现时将数字与数据库中的列匹配

Question

I need help with a loop to echo 1-30 but after the 5th count list the numbers and match to a column in the database. The numbers are random in the database such as 1,2,4 but I would like to match with the numbers ($x++):

    $x=1;
    foreach($forDB->results() as $f) {
    $x++;
    $id = $f->id;
    $name = $f->string;
     if($x<=5) {
        if($id == $x) {
            echo '<div class="list-matched">'.$x.' = '.$name.'</div>,';
        } elseif($id != $x) {
            echo '<div class="list">'.$x.'</div>,';
        }
        if($x == 5){
            echo ' | ';
        }
     }elseif($x<=15) {
        if($id != $x) {
            echo '<div class="list-matched">.$x.' = '.$name.'</div>,';
        }elseif($id != $x) {
            echo '<div class="list">'.$x.'</div>,';
        }
     }
    }

Now the results are good up to: 1 = stringone, 2 = stringtwo, 3, 4, 5 | 6, 7, 8, 9

but then stops at 9.. and it does not echo the 4th value from the database or any numbers that are jumping around the columns (ex. 1,2,4,6,9,13,15).. Seems to be getting 1 and 2 fine but when it skips one or more numbers it stops. and tested by echo'ing the id after: if }elseif{$id != $x) { //echo x } echo $id;.. but it goes 1,2 and stops.. Please help!