应在PHP中选择行时显示图像的列

Question

This may be a simple question. But as a beginner I need help.
In my table created by simple HTML and used PHP to extract values from mysql, I need a column which should display an image on selecting the row from the table. How is it possible in PHP. Is it make use of jQuery to load dynamically. Please help.

Answer 1

If you want to display image on click, then you need to use Jquery.

For simple you can create this feature like this,

First load all the images in table in specific class defined row but make its css attribute display:none;

in jquery you can write script like this....

$('.class-of-row').click(function(){
    $('.class-of-row.class-of-image').css("display","none"); /* to hide other image on click on specif row */
    $(this).child('.class-of-image').css("display","block"); /* To make visible image of clicked row */
});