I want to get results from 2 table using SQL INNER JOIN but it's only showing 1st result not others one. If i select other data then it's showing following error message:
Warning: Invalid argument supplied for foreach() in D:\software installed\xampp\htdocs\contact-management\getContactDetails.php on line 14
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Description of my functionality:
I have 2 table in my database.
-
contact_details:
cdid, family_name, given_name, work_phone, mobile_phone, email, email_private, cid
-
contact_docs:
docid, cdid, file_name, file_des
I'm showing all contacts (only family_name) from database. After select each contacts then it's showing/loading all contact details using Jquery/ajax which is showing on a HTML FORM. So now it's showing contact_details data on the html input type = text field. But I also need show contact_docs data which is actually files.
So when I send a request to the server using jQuery/ajax I've to use SQL inner join query to get the result from both table based on id (cdid)
. But unfortunately my inner join query is not working properly. It's not showing all contact details data on the html form if I select different contacts. Only showing 1st result.
My questions are:
How do I fix this inner join query?
How do I show the uploaded file on the form (file link would be better) when whole form is load with all data from 2 table ?
Note: I can successfully edit/insert the data to database but issue about showing the data with file.
This is my code:
Html page:
<div id="showContactsDetails">
<h2>Individual Record Details</h2>
<div style=" visibility:hidden;" id="visiable">
<span class="mandatory"><sub>* Required</sub></span>
<!--success update -->
<div id="success"></div>
<form action="" method="post" enctype="multipart/form-data" id="all_contact_details">
<table width="450" border="0" cellspacing="0" cellpadding="0">
<input type="hidden" name="cdid" id="cdid"/>
</tr>
<tr>
<td>Company Name</td>
<td><input type="text" name="company_name" id="company_name" disabled="disabled"/></td>
</tr>
<tr>
<td>Family name</td>
<td><input type="text" name="family_name" id="family_name"/></td>
</tr>
<tr>
<td>Given name</td>
<td><input type="text" name="given_name" id="given_name"/></td>
</tr>
<tr>
<td>Work Phone</td>
<td><input type="text" name="work_phone" id="work_phone"/></td>
</tr>
<tr>
<td>Mobile Phone</td>
<td><input type="text" name="mobile_phone" id="mobile_phone"/></td>
</tr>
<tr>
<td>Email address</td>
<td><input type="text" name="email" id="email"/></td>
</tr>
<tr>
<td>Private email address</td>
<td><input type="text" name="email_private" id="email_private"/></td>
</tr>
<tr>
<td>Upload your document</td>
<td><input type="text" name="file_des_1" id="file_des1" placeholder="short description of your document" class="shor"/><span class="mandatory"><sup>*</sup></span></td>
<tr>
<td></td>
<td align="left"><input name="file1" type="file" id="file" class="file"/></td>
<span class="file_des_1"></span>
</tr>
<tr>
<td></td>
<td><input type="text" name="file_des_2" id="file_des2" placeholder="short description of your document" class="shor"/><span class="mandatory"><sup>*</sup></span></td>
<tr>
<td></td>
<td align="left"><input type="file" name="file2" id="file_2" class="file"/></td>
</tr>
<tr>
<td></td>
<td><input type="text" name="file_des_3" id="file_des3" placeholder="short description of your document" class="shor"/><span class="mandatory"><sup>*</sup></span></td>
<tr>
<td></td>
<td align="left"><input type="file" name="file3" id="file_3" class="file"/></td>
</tr>
<tr>
<td></td>
<td><input type="text" name="file_des_4" id="file_des4" placeholder="short description of your document" class="shor"/><span class="mandatory"><sup>*</sup></span></td>
<tr>
<td></td>
<td align="left"><input type="file" name="file4" id="file_4" class="file"/></td>
</tr>
<tr>
<td> </td>
<td><input type="button" name="submit" value="Update Details" class="submit" id="upload"/></td>
</tr>
</table>
</form>
</div>
</div><!--showContactsDetails-->
jQuery/Ajax page:
//edit the form....................
<script>
$('body').on('click', '#upload', function(e){
e.preventDefault();
var formData = new FormData($(this).parents('form')[0]);
$.ajax({
url: 'editContactDetails.php',
type: 'POST',
xhr: function() {
var myXhr = $.ajaxSettings.xhr();
return myXhr;
},
success: function(data){
$("#success").html(data);
document.getElementById("all_contact_details").reset();
},
data: formData,
cache: false,
contentType: false,
processData: false
});
});
//load the html form with all contact details..................................................
function getDetails(id) {
id = id;
$.ajax({
url: 'getContactDetails.php',
type: 'post',
data: {'id' : id},
dataType : 'json',
success: function( res ) {
document.getElementById("visiable").style.visibility = "visible";
console.log(res);
$.each( res, function( key, value ) {
console.log(key, value);
$('input[type=text][name='+key+']').val(value);
$('input[type=hidden][name='+key+']').val(value);
$('textarea[name='+key+']').val(value);
});
}
});
}
</script>
Php page (getContactDetails.php):
<?php
ob_start();
require_once("config.php");
$id = (int) $_POST['id'];
$sql = mysql_query("SELECT contact_details.cdid, contact_details.family_name, contact_docs.file_name FROM contact_details INNER JOIN contact_docs ON contact_details.cdid = contact_docs.cdid WHERE contact_docs.cdid = '$id'");
$res = mysql_fetch_array($sql);
$data = array();
foreach( $res as $key => $value ) {
$data[$key] = $value;
}
echo json_encode($data);
?>
I'm a new in web development field. So may be my code is wrong that's why your help is greatly appreciated :)