如何从表单中选择html从数据库mysql获取数据？

Question

i was trying to show data from database into tag> select html. here is the code :

<?php
require 'koneksi.php';
$sql_select = "SELECT nama_supplier FROM supplier"; 
$hasil = mysql_query($sql_select);
  if(!$hasil) {
  echo "data not found ".mysql_error();
  }
  mysql_close();
?>
<div class="par control-group">
    <label class="control-label" for="supplier">Supplier</label>
    <select name="supplier" class="uniformselect">
    <?php
       while($baris = mysql_fetch_array($hasil)){
       echo "<option value='$baris'>".$baris."</option>";           
       }
    ?>
    </select>
</div>

the problem is, the output doesn't show the option value from database. the output only print 'array'. here is screenshot : image . i know that it has to be something simple that i am missing but seriously i cannot figure it out. please anyone help, thanks!

Answer 1

You need to select a row from the $baris variable which stands as an array

echo $baris['Coulmn you want'];

If you don't the variable $baris will be equal to something like that. You need to select which column you want.

([id]->1,[name]->'user',...,['email']->[e-mail])