使用HTML表单与PHP [重复]

Question

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• “Notice: Undefined variable”, “Notice: Undefined index”, and “Notice: Undefined offset” using PHP 28 answers

I'm new to PHP and learning PHP by myself.Here I want to get the output value of text fields using php code but it gives me an error .can anyone point out the error .

here is my code test.php .................

 <?php

 $nameone=$_POST['nameone'];
 echo $nameone;

 ?>


 <hr/>
 <h1>fgdhgf</h1>
 <form action="test.php" method="POST">
 <input type='text' id='nameone' name='nameone' >
 <input type='text'name='name2'>
 <input type="submit" value="submit" name="roll">
 </form>

</div>

Answer 1

you have to change the (action = "test.php") to (action = "") to inform the HTML to look inside the same page for php code . You are telling the HTML to look for another test.php page in your directory.

and you have to put @ sign before ($_POST['someone']) to escape the first undefined index error when you load the page .

Sorry for my poor formatting , I am from a smartphone