dsgwoh7038 2013-12-20 05:46
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PHP的日期/时间差异给了我额外的一小时

I'm trying to following code to get the difference in hours between 2 date/time values. The difference should be 47.82, but the result is 48.82. I can't figure out why.

$time1 = '11/03/2013 15:28:00';
$time2 = '11/01/2013 15:39:00';

$hourdiff = round((strtotime($time1) - strtotime($time2))/3600,2);
echo $hourdiff;

Any help is greatly appreciated.

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  • 普通网友 2013-12-20 06:47
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    The difference is likely due to daylight saving time.

    You could set the dates to UTC which removes this issue.

    $time1 = '11/03/2013 15:28:00 UTC';
    $time2 = '11/01/2013 15:39:00 UTC';
    
    $hourdiff = round( ( strtotime( $time1 ) - strtotime( $time2 ) ) / 3600, 2 );  
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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