I'm working on the PHP code of someone else and can't find the source file of a certain content. I'm looking for a solution which gives me an easy access to the file name of anything displayed on the website. I did some researches but don't know how to work with that and was hoping to find something like Firebug for the CSS of the website.
The PHP is this:
<?PHP
function getFileList($dir)
{
// array to hold return value
$retval = array();
// add trailing slash if missing
if(substr($dir, -1) != "/") $dir .= "/";
// open pointer to directory and read list of files
$d = @dir($dir) or die("getFileList: Failed opening directory $dir for reading");
while(false !== ($entry = $d->read())) {
// skip hidden files
if($entry[0] == ".") continue;
if(is_dir("$dir$entry")) {
$retval[] = array(
"name" => "$dir$entry/",
"type" => filetype("$dir$entry"),
"size" => 0,
"lastmod" => filemtime("$dir$entry")
);
} elseif(is_readable("$dir$entry")) {
$retval[] = array(
"name" => "$dir$entry",
"type" => mime_content_type("$dir$entry"),
"size" => filesize("$dir$entry"),
"lastmod" => filemtime("$dir$entry")
);
}
}
$d->close();
return $retval;
}
?>