PHP删除内容中的部分URL

Question

I have a string which contains a varying number of Url's. I would like to remove the "?category_id=x" part of every Url. x will be a changing number.

var old_string = "some text <a href='/platforms/item/something?category_id=x'>some text</a> some more text <a href='/platforms/item/something?category_id=x'>some text</a>..." 

var new_string = "some text <a href='/platforms/item/something'>some text</a> some more text <a href='/platforms/item/something'>some text</a>...." 

How can I do this. Regex?

Answer 1

Answers using parse_url are best if you've already extracted the URLs from your string. I'm assuming you have not.

<?php
$old_string = "some text <a href='/platforms/item/something?category_id=x'>some text</a> some more text <a href='/platforms/item/something?category_id=x'>some text</a>...";

// if you know there won't be any other url parameters:
$new_string = preg_replace('!\?category_id=(x|\d+)!','', $old_string );

// otherwise, remove query string from all URLs:
$new_string = preg_replace('!(href=(?:\'|")[^\?\'"]+)\?[^\'"#]*!','\1', $old_string );

Your code looks like JavaScript though. The second regexp in JS would be:

old_string.replace( /(href=(?:"|')[^\?'"]+)\?[^'"#]*/g, '$1' );