php mysql_fetch_array查询帮助

Question

Hi i'm trying to process the mysql_fetch_array query below and simplify the code so only 1 query is ran for both sets, is that possible

<select name=[set1]>    
<?php
$set1 = mysql_fetch_array(mysql_query("SELECT `Locale` FROM `language` WHERE `Setting` = '1' ORDER BY FormatSet"));
while($row = $set1){
    echo "<option value=\"$set1\">$set1</option>
";
}
?>
                </select>
                <select name=[set2]>    
<?php
$set2 = mysql_fetch_array(mysql_query("SELECT `Locale` FROM `language` WHERE `Setting` = '2' ORDER BY FormatSet"));
while($row = $set2){
    echo "<option value=\"$set2\">$set2</option>
";
}
?>
</select>

Answer 1

<?php 
$textSet1 = '<select name=[set1]>';
$textSet2 = '<select name=[set2]>';
$set = mysql_query("SELECT `Locale`, `Setting` FROM `language` WHERE `Setting` in ('1','2') ORDER BY FormatSet");
while($row = mysql_fetch_array($set)){
    if ($row['Setting'] == '1')
         $textSet1 .= '<option value="'.$row['Locale'].'">'.$row['Locale'].'</option>';
    else
         $textSet2 .= '<option value="'.$row['Locale'].'">'.$row['Locale'].'</option>';
}
$textSet1 .= '</select>';
$textSet2 .= '</select>';

echo $textSet1;
echo $textSet2;
?>