I have a strtotime date in a variable. I need to find out the 4th day from that variable
$strtotime1=strtotime('06/17/2012');
I need to find out the 4th day (i.e. 06/21/2012) in strtotime format.
I have tried with:
$strtotime2=$strtotime1+4*60 * 60;
But it's not working.