如何从数据库中显示登录用户的图像？

Question

Say if a user uploaded multiple images to their profile page, how would I display that specific user's images? I tried I did something like this:

$db = mysqli_connect("localhost", "root", "", "testdb");
        $sql = "SELECT * FROM users ORDER BY id DESC";
        $result = mysqli_query($db, $sql);
        while ($row = mysqli_fetch_array($result)) {
            echo "<a href='profiles/uploads/".$row['image']."> ";
                echo "<img  id='img_div' title='".$row['image']."' alt='".$row['image']."'  src='profiles/uploads/".$row['image']."'/>";
                //echo "<p id='img_div'>".$row['desc']."</p>";
                echo "</a>";

But I feel like this is terribly wrong because it is showing everyone's images and not the user's images. I tried looking up answers, but can't seem to find one.

Answer 1

Try this:

You need to set user in sql query like id = 10.

And also missing ' last of this line: echo "<a href='profiles/uploads/".$row['image'].">";

<?php
$user_id = 10;
$db = mysqli_connect("localhost", "root", "", "testdb");
$sql = "SELECT * FROM users WHERE id = ". $user_id ." LIMIT 1";
$result = mysqli_query($db, $sql);

while ($row = mysqli_fetch_array($result)) {
    echo "<a href='profiles/uploads/". $row['image'] ."'>";
    echo "<img id='img_div' title='".$row['image']."' alt='".$row['image']."' src='profiles/uploads/".$row['quotes']."'/>";
    //echo "<p id='img_div'>".$row['desc']."</p>";
    echo "</a>";
}
?>