duaiwu8385 2013-09-17 11:42
浏览 16
已采纳

in_array没有找到存在的值?

Here is the code to check if the contact_id is present in the pool of particular user's pool

function checkid()
{
    $conn = connectPDO();

    $query = "SELECT contact_id FROM contacts WHERE contact_by = :cby";
    $st = $conn->prepare( $query );
    $st->bindValue( ':cby', $this->contact_by, PDO::PARAM_INT );
    $st->execute();
    $row = $st->fetchALL();
    $conn = null;

    print_r($this->contact_id); //1
    print_r($row);     //Array ( [0] => Array ( [contact_id] => 1 [0] => 1 ) [1] => Array ( [contact_id] => 3 [0] => 3 ) ) 

    if( !in_array( $this->contact_id, $row ))
    {
        echo 'You are not authorised to update the details of this contact';
    }
}

Here is the url:

http://localhost/contmanager/home.php?action=update&contactid=1

One thing i noticed is that, when i use fetch instead of fetchall, it works fine for contact_id '1' but fails when using fetchALL.

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2条回答 默认 最新

  • dongzhuandian3292 2013-09-17 11:43
    关注

    in_array not works for multidimentional array's, A workaroud will be:

    foreach( $row as $each ){  #collect all the ids in an array
        $temp[] = $each['contact_id'];
    }
    

    Then check for in_array:

    if( !in_array( $this->contact_id, $temp )){
        //your code here
    }
    
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