dongliyi967823 2018-05-08 19:27
浏览 132
已采纳

PHP复选框返回值(选中/未选中)并更新

I have a form that submits a load of checkboxes - This works fine.

I then have a form i can open which will display said checkboxes and will be checked or not checked based on the SQL query ran.

SQL query runs ok with echo but I cannot get the box to show as checked. After this I want to be able to check uncheck the boxes and update via an SQL.

<?php
    session_start();
    ini_set('display_errors', 1); error_reporting(-1);
    $data = $_GET['id'];
    require 'connect.php';
    $sql1 = "SELECT id, phone, email, pager
    FROM [dbo].[preference] WHERE id = '$data'";
    $stmt1 = sqlsrv_query($con,$sql1);
    if( $stmt === false) {
    die( print_r( sqlsrv_errors(),true));
}   
        while ($row1 = sqlsrv_fetch_array($stmt1)){
        $id = $row1['id'];
        $phone = $row1['phone'];
        $email = $row1['email'];
        $pager = $row1['pager'];
}
?>


<td><input type="checkbox" name="phone" class="check" value="1">phone</td>
<td><input type="checkbox" name="email" class="check" value="1">email</td>
<td><input type="checkbox" name="pager" class="check" value="1">pager</td>

How can I resolve this?

  • 写回答

2条回答 默认 最新

  • dplht39359 2018-05-08 19:39
    关注

    I'm still not really sure I understand the question...

    You load the script after an update. The rendering reflects the current state at that time. You submit to the script, perform the update, then reload... which then renders that updated state...

    <?php
            ...
            $id = $row1['id'];
            $phone = $row1['phone'];
            $email = $row1['email'];
            $pager = $row1['pager'];
    }
    ?>
    
    
    <td><input type="checkbox" name="phone" class="check" value="1" <?= (!empty($phone)) ? 'CHECKED' : '' ?>>phone</td>
    ...
    

    High level...

    //pseudo code for a CRUD script...
    
    //is this a POST?
    if (isset($_POST['submit')) {
      //validate user input, never trust the user, beware SQL injection...
    
      //if passes validation update the values in the database
    
      //if not, raise error flags, re-display the form (you'll see you need to use the supplied POST data, that failed to validate, as the inputs values or you'll lose the provided input, think it will make sense when you het here...)
    }
    
    //here could be a POST or initial load... could even flow here to provide confirmation of update and show new values
    
    //load current data from database
    
    //render form based off vurrent values
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
查看更多回答(1条)

报告相同问题?

悬赏问题

  • ¥20 机器学习能否像多层线性模型一样处理嵌套数据
  • ¥20 西门子S7-Graph,S7-300,梯形图
  • ¥50 用易语言http 访问不了网页
  • ¥50 safari浏览器fetch提交数据后数据丢失问题
  • ¥15 matlab不知道怎么改,求解答!!
  • ¥15 永磁直线电机的电流环pi调不出来
  • ¥15 用stata实现聚类的代码
  • ¥15 请问paddlehub能支持移动端开发吗?在Android studio上该如何部署?
  • ¥20 docker里部署springboot项目,访问不到扬声器
  • ¥15 netty整合springboot之后自动重连失效