drgdn82648 2015-09-18 11:28
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Preg替换回调

I am trying to work out how to pop an optional group into a preg_replace_callback but I am having trouble matching the + character

Here is the code I have this far

$pattern=preg_replace_callback('~:(?P<_param>[Aa-zZ0-9_\-]+)(?:(P<_mod>[^/]))?~',

    function($matches)
    {
        print_r($matches);
        $key=$matches[1];
        return '(?<'.$matches['_param'].'>'.$matches['_mod'].')';
    }
    ,$subject);

This generates the following pattern

/category/(?<foo>)/(?<baz>.)+/(?<bar>.)+/(?<harry>.)+/foo

For the following string

/category/:foo/:baz.+/:bar.+/:harry.+/foo

As you can see it's carrying over the . but not the plus, essentially I would like it to carry (into the named _mod capture group) any modifier that I append to a :variable.

I am not very good at regex so I'm amazed to have gotten this far and any help on my quest would be greatly appreciated

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1条回答 默认 最新

  • duanqiu2064 2015-09-18 11:35
    关注

    Add a quantifier after the group _mod:

    $pattern=preg_replace_callback('~:(?P<_param>[Aa-zZ0-9_\-]+)(?:(?P<_mod>[^/]+))?~',function($matches){
    //                                                                  here ___^
    

    question: what do you think [Aa-zZ] matches?

    I guess you want [A-Za-z0-9_\-]+ or [\w-]

    Furthermore, preg_replace would suffice here:

    $pattern = preg_replace('~:([\w-]+)(?:([^/]*))?~', "(?<$1>$2)", $subject);
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

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