使用日期Diff（）值，如整数[PHP]

Question

I like to use date diff() value like integer number.

For example : I have two dates; 2016-04-22 and 2016-04-30

$diff = date2->diff(date1);
$diff_number_converted = "$diff";
$diff_plusone =" $diff_number_converted" + 1;

echo $diff_number_converted . "<br/>";
echo $diff_plusone;

And result is:

8
9

I solved my problem :)

Answer 1

Not exactly answer there is.

I'd like to convert diff () value to integer. For example :

$diff = date2 - > diff (date1) ;

for($i=0; $i=$diff; $i++) {
// some code
} 

Above code is not working because of diff value is date interval.