dtpt75860 2014-06-02 19:27
浏览 36

使用php简单删除查询

I am trying to create a delete query from HTML using PHP:

HTML:

<form method="POST" action="" >
    ID<input type="text" name="x" />
    <input type="submit"  value="DELETE" name="del"/>
</form>

PHP:

<?php
$connection = mysql_connect("localhost","root","") or die ("Couldn't connect to server");
$db = mysql_select_db("smap", $connection) or die ("Couldn't select database");
if(isset($_POST['del'])) {
    $a = $_POST['x'];
    $sql = mysql_query("DELETE syracuseone WHERE ID ='$a'";)
    if(mysql_query($sql)) {
        echo "deleted";
    } else {
        echo "fail";
    } 
}
?>

I get this error:

Notice: Undefined index: x

Any assistance from stack?

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1条回答 默认 最新

  • duanduo7400 2014-06-02 19:31
    关注

    It means that your post value was not passed to the next page, you can do something like this $a = isset($_POST['x']) ? $_POST["a"] : 0;

    Take a look, here is it's usage:

    <form method="POST" action="" >
        ID<input type="text" name="x" />
        <input type="submit"  value="DELETE" name="del"/>
    </form>
    
    <?php
    $connection = mysql_connect("localhost", "root", "") or die("Couldn't connect to server");
    $db         = mysql_select_db("smap", $connection) or die("Couldn't select database");
    if(isset($_POST['del'])){
        $a   = isset($_POST['x']) ? $_POST["a"] : 0;
        $sql = mysql_query("DELETE FROM syracuseone WHERE ID ='$a'");
        if(mysql_query($sql)){
            echo "deleted";
        }else{
            echo "fail";
        }
    }
    ?>
    
    评论

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