MySQL在控制台中工作，但从PHP执行时会出现500内部服务器错误

Question

I have a small php file which just creates the tables in a database. I've spent days trying to debug it and it's left me stumped. It poops out with an ugly HTTP Error 500 (Internal Server Error): An unexpected condition was encountered while the server was attempting to fulfil the request. when I execute the queries. However, when I print out the queries and paste them into the database, it works fine.

I also noticed that "table already exists" would flash when entering the queries manually, but disappear and work quickly. Similar to this question Mysql 1050 Error "Table already exists" when in fact, it does not , but I've tried deleting and remaking the database without success. If anyone could help it'd be greatly appreciated. Here's the php code

$users = 'CREATE TABLE users (
        id int UNSIGNED NOT NULL AUTO_INCREMENT,
        PRIMARY KEY(id),
        username varchar(30) NOT NULL, UNIQUE(username),
        password varchar(30) NOT NULL,
        email varchar(50) NOT NULL, UNIQUE(email),
        confirmation_code int NOT NULL,
        confirmation_tries int NOT NULL
    ) ENGINE=InnoDB';

$players = 'CREATE TABLE players (
        id int UNSIGNED NOT NULL,
        FOREIGN KEY(id) REFERENCES users(id),
        cost int UNSIGNED NOT NULL,
        strategy TINYINT UNSIGNED NOT NULL,
        age int UNSIGNED NOT NULL,
        %s
    ) ENGINE=InnoDB';
$records = array();
for ($i = 0; $i < NUM_RECORDS; $i++) {
    $records[$i] = sprintf('record_%d int UNSIGNED NOT NULL', $i);
}
$players = sprintf($players, implode(', ', $records));

$kingdoms = 'CREATE TABLE kingdoms (
        id int UNSIGNED NOT NULL,
        FOREIGN KEY(id) REFERENCES users(id),
        location int UNSIGNED NOT NULL,
        building text NOT NULL,
        level int UNSIGNED NOT NULL,
        troops int UNSIGNED NOT NULL
    ) ENGINE=InnoDB';

$inboxes = 'CREATE TABLE inboxes (
        recipientID int UNSIGNED NOT NULL,
        FOREIGN KEY(recipientID) REFERENCES users(id),
        messageID int UNSIGNED NOT NULL AUTO_INCREMENT,
        PRIMARY KEY(messageID),
        message text NOT NULL,
        date DATETIME NOT NULL
    ) ENGINE=InnoDB';

$lastActions = 'CREATE TABLE last_actions (
        id int UNSIGNED NOT NULL,
        FOREIGN KEY(id) REFERENCES users(id),
        history text
    ) ENGINE=InnoDB';

$news = 'CREATE TABLE news (
        id int UNSIGNED NOT NULL,
        FOREIGN KEY(id) REFERENCES users(id),
        entries text
    ) ENGINE=InnoDB';

/*
$dbh->exec($users);
$code = $dbh->errorCode();
if ($code !== '00000') {
    var_dump($code);
    echo '111111';
    exit;
}
$dbh->exec($players);
$code = $dbh->errorCode();
if ($code !== '00000') {
    var_dump($code);
    echo '22222';
    exit;
}
$dbh->exec($kingdoms);
$code = $dbh->errorCode();
if ($code !== '00000') {
    var_dump($code);
    echo '33333';
    exit;
}
$dbh->exec($inboxes);
$code = $dbh->errorCode();
if ($code !== '00000') {
    var_dump($code);
    echo '44444';
    exit;
}
$dbh->exec($lastActions);
$code = $dbh->errorCode();
if ($code !== '00000') {
    var_dump($code);
    echo '555555';
    exit;
}
$dbh->exec($news);//
$code = $dbh->errorCode();
if ($code !== '00000') {
    var_dump($code);
    echo '666666';
    exit;
}//*/
echo $users . ";" . $players . ";" . $kingdoms . ';' . $inboxes . ';' . $lastActions .';' . $news;

Answer 1

HTTP Error 500 (Internal Server Error) is error response of a HTTP request.
Use mysql_error or whatever you are using to echo the response of mysql_query in order to get error. or check error_logs. Its not exactly returned by mysql.

If your error_reporting is off, make it ON.

error_reporting( E_ALL | E_STRICT ); 
ini_set( 'display_errors', 1 )