dougaoxian8922 2012-11-14 14:39
浏览 42
已采纳

检查会话 - php不打印[关闭]

<?php session_start();
$_SESSION['loggedIn'] = "no";
echo "Logged In: ". $_SESSION['loggedIn'];

if($_SESSION['loggedIn']=="yes"): 
    echo "logged in";
}
else{
    echo "not logged in";
}
?>

I am simply trying to check if the session "loggedIn" is yes or no, but the program doesn't print anything.

Why does it not print anything?

  • 写回答

4条回答 默认 最新

  • dsvd407787736 2012-11-14 14:41
    关注

    You are using alternative if/then as well as regular syntax.

    if($_SESSION['loggedIn']=="yes"):
    

    should be

    if($_SESSION['loggedIn']=="yes"){
        echo "logged in";
    }
    else{
        echo "not logged in";
    }
    

    its a simple syntax error

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
查看更多回答(3条)

报告相同问题?

悬赏问题

  • ¥15 如何让企业微信机器人实现消息汇总整合
  • ¥50 关于#ui#的问题:做yolov8的ui界面出现的问题
  • ¥15 如何用Python爬取各高校教师公开的教育和工作经历
  • ¥15 TLE9879QXA40 电机驱动
  • ¥20 对于工程问题的非线性数学模型进行线性化
  • ¥15 Mirare PLUS 进行密钥认证?(详解)
  • ¥15 物体双站RCS和其组成阵列后的双站RCS关系验证
  • ¥20 想用ollama做一个自己的AI数据库
  • ¥15 关于qualoth编辑及缝合服装领子的问题解决方案探寻
  • ¥15 请问怎么才能复现这样的图呀