dongmou5628 2013-04-27 19:36
浏览 16
已采纳

条件简单算法[关闭]

My simple brain can't seem to put this together.

I want to do a check on some code to say:

if (($limit == 0) || ($count < $limit))
//do stuff
else
//exit

The values of limit are either 0, 1 or 4. Where 0 represents "unlimited" (don't ask).

So really what I want to say is

if limit == 0 or count < limit (except when limit ==0)

What is the best way to structure that?

  • 写回答

2条回答 默认 最新

  • douju7765 2013-04-27 19:52
    关注

    It would be helpful if you var_dump $limit and $count to make sure their types are correct. Your code is correct and when $limit is 0, it should evaluate to TRUE and the code should be run.

    <?php
    $limit = 0;
    if ($limit == 0 || non_exisint_func()) {
      echo 'yeah';
    }
    

    http://3v4l.org/SH9mE - You will see that the second condition is not even evaluated.

    Your condition will always pass if you put a NULL, (bool) FALSE or (string) 0.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
查看更多回答(1条)

报告相同问题?

悬赏问题

  • ¥15 在获取boss直聘的聊天的时候只能获取到前40条聊天数据
  • ¥20 关于URL获取的参数,无法执行二选一查询
  • ¥15 液位控制,当液位超过高限时常开触点59闭合,直到液位低于低限时,断开
  • ¥15 marlin编译错误,如何解决?
  • ¥15 有偿四位数,节约算法和扫描算法
  • ¥15 VUE项目怎么运行,系统打不开
  • ¥50 pointpillars等目标检测算法怎么融合注意力机制
  • ¥20 Vs code Mac系统 PHP Debug调试环境配置
  • ¥60 大一项目课,微信小程序
  • ¥15 求视频摘要youtube和ovp数据集