php重定向页面未打开到新位置但在div中打开ajax响应文本[关闭]

Question

php redirect page is not open to new location but open in the div where ajax response text

PHP>ISSUE>PHP + AJAX + HTML FORM>REDIRECT [?]=NEW LOCATION.

(?)=PAge should be open in new page but open in the div #ajax

desire:Open in new page not in the div

---

HTML CODE:

  <form id="form1" name="form1" action="login_success.php" onSubmit="return Ajxfunction()">

  <input type="text" name="username" autocomplete="off" id="username">
  <div id="validate"></div>
 <input id="passowrd" type="password" autocomplete="off" name="password">
   <div id="validate2"></div>
  <input type="checkbox" name="checkbox" id="checkbox">
  Stay Signed in <span>Forgetget Paswoard</span>
  <br>
  <input class="submit" id="button" type="button" value="SignIn" onClick=" Ajxfunction()" >
  <div id="ajaxDiv"></div>
  </form>

AJAX CODE

      function Ajxfunction(){

              var text= text2="";
              var boolean=false;
            var user = document.forms["form1"]["username"].value;
             var password = document.forms["form1"]["password"].value;


              if ( user==null  || user == "") {
                text = "Please Enter user name";

                 boolean=false;

            } else {
                text = "";
                boolean=true;

            }

             if ( password==null  || password == "") {
                text2 = "Please Enter Password";

                 boolean=false;

            } else {
                text2 = "";
                boolean=true;

            }

         document.getElementById("validate").innerHTML =text;
         document.getElementById("validate2").innerHTML =text2;

         if(boolean){
                ajaxFunction();




             }

             //return true;
        }


        function ajaxFunction(){
         var ajaxRequest;  // The variable that makes Ajax possible!

         try{
           // Opera 8.0+, Firefox, Safari
           ajaxRequest = new XMLHttpRequest();
         }catch (e){
           // Internet Explorer Browsers
           try{
              ajaxRequest = new ActiveXObject("Msxml2.XMLHTTP");
           }catch (e) {
              try{
                 ajaxRequest = new ActiveXObject("Microsoft.XMLHTTP");
              }catch (e){
                 // Something went wrong
                 alert("Your browser broke!");
                 return false;
              }
           }
         }
         // Create a function that will receive data 
         // sent from the server and will update
         // div section in the same page.
         ajaxRequest.onreadystatechange = function(){
           if(ajaxRequest.readyState == 4){
              var ajaxDisplay = document.getElementById('ajaxDiv');
              ajaxDisplay.innerHTML = ajaxRequest.responseText;
           }
     }

     var username1="";
    var password1="";
     username1=document.forms["form1"]["username"].value;
     password1=document.forms["form1"]["password"].value;
    var queryString = "?username=" + username1 ;
     queryString +=  "&password=" + password1;
    /* var queryString = "?username1=" + username1 ;
     queryString +=  "&password1="+password1; /*+ "&sex=" + sex*/
     ajaxRequest.open("GET", "Checklogin.php"+queryString, true);
     ajaxRequest.send(null); 
    }

PHP CODE:Checklogin.php

   <?php 



 $link = mysqli_connect('localhost','root','root','fly') or die("Error " .mysqli_error($link)); 


 $user="";
 $pass="";
if(isset($_GET['username'])){$user = $_GET['username'];} 
if(isset($_GET['password'])){ $pass = $_GET['password'];} 



$user = mysqli_real_escape_string($link,$user);
$pass = mysqli_real_escape_string($link,$pass);


/* $result = mysqli_query($link,"SELECT * FROM `useraccount` where username='$username' and password='$password' ");
*/ 
$msg="";
 $result = mysqli_query($link,"SELECT * FROM `useraccount` where username='$user' && password='$pass' ");
 $count = mysqli_num_rows($result);
 try{

     /*while($row = mysqli_fetch_array($result)) {
  echo $row['username'] . " " . $row['password'];
  echo "<br>";
}*/
 if($count==1){
    // session_start();
    // $_SESSION["username"] = $user;
    // $_SESSION["password"] = $pass;

//  $_SESSION['login_user']=$result['useraccount']; //Storing user session value.
//  $_SESSION['login_user']="HAroon"; //Storing user session value.
    echo "Right Password";
header("Location:http://www.formget.com/app/");
 // header('Location: login_success.php');

}
else {
$msg ="Wrong Username or Pdasswor";

  mysqli_close($link);

}
}catch(Exception $e){
$msg=   " Wrong";

    }

    echo $msg;

?>

========

Answer 1

You can not redirect page with Location header for ajax requests. You must get some response text for ajax and redirect user using parsed response text. This is how to redirect browser with JS code

if (responseText == 'OK'){ document.location.href = 'http://example.com/';}