I made this code where I define an array, fliepath, in which I store the locations of some files.
include 'last_file.php'; // Include the function last_file
$last_file = last_file(); // assign to the function a variable and call the function last_file
// Connect to the database
include('connect_thesis.php');
// Defining an array, which has the three paths to the three different gps receivers
$file_path[0] = "/Applications/MAMP/htdocs/php_test/check/".$last_file[0];
//echo $file_path[0]; echo "<br>";
$file_path[1] = "/Applications/MAMP/htdocs/php_test/check2/".$last_file[1];
//echo $file_path[1]; echo "<br>";
$file_path[2] = "/Applications/MAMP/htdocs/php_test/check3/".$last_file[2];
//echo $file_path[2]; echo "<br>";
Then I made a function called insert() which I want to take as input the $file_path[0]:
function insert($file_path){
$fh = fopen($file_path,'r') or die ("Could not open:".mysql_error()).......;
I call the function from the main script as:
insert($file_path[0]);
I am new in programming and I am sure somewhere I am missing something basic! The problem is that the function doesn't run!!! Can you help me? Thanx D.
I THINK I DONT PASS CORRECTLY THE VALUE TO THE FUNCTION. CAUSE I GET NOTHING AS AN ERROR!