I'm developing a simple login form for my website. And to do that I thought to use ajax to connect with php to validate users. However to do that I cannot get output from ajax.
<script>
function submitForLogin()
{
$.ajax({
type: "POST",
url: "php/login.php",
data: { email: "example@abc.com",password:"123" }}).done(function(data){alert(data);});
}
</script>
When user clicks on login button it calls submitForLogin() function.
Above part of the code I've placed in my login.html file. To validate whether this works or not I simply replaced data values of email and password with hard coded values.
Note : example@abc.com and 123 both email and password stored in Wamp server database.
This is the PHP file :
<?php
$userEmail=$_POST['email'];
$userPass=$_POST['password'];
$servername ="localhost";
$username="root";
$password="";
$dbname="AS2014459";
//To create a connection
$con = mysqli_connect($servername,$username,$password,$dbname); //check connection
if(!$con){
die("Connection failed: ".mysqli_connect_error());
}
$sql="SELECT Email,Password FROM USERTABLE WHERE Email='".$userEmail."'";
$results=mysqli_query($con,$sql);
if(mysqli_num_rows($results)>0)
{
echo "userExist";
}
else
{
echo "fakeUser";
}
mysqli_close($con);
?>
Whenever I run php file only (with $userEmail and $userPass having previous hard coded values) php prints userExist output. But using ajax I cannot get that in an alert box.
Is there something I missing? I'm running the website in wamp server too.
UPDATE
When I check console errors it shows;
And when I click on login.html line 112, it shows;
And ideas guys? Also, none of the solutions provided so far gave me successful answer for the question.
There was a jquery error and now it's fixed. But syntax error exists.
