duanmei4149 2013-08-20 15:47
浏览 56

将动态PHP变量转换为Javascript函数

I am trying to pass $post; a variable created in a mysql query, to javascript function showDiv. Currently this doesnt work.

$post = $row['id'];
?>


<script type="text/javascript">
  function showDiv() {  
    var note = "<?php echo $post ?>";
    document.getElementById("<?php echo $post; ?>").style.display = "inline";      
  }
</script>

<?php 
  $addnote = '<input type="button" value="addnote" onclick="showDiv()"><div id="'.$postid.'"  style="display:none;" class="'.$postid.'"> WELCOME</div>';

But if I change $post to have a html value e.g

$post = '11';

then this code works.

I am novice in javascript so please be gentle, Any help is greatly appreciated. Thank you.

  • 写回答

3条回答 默认 最新

  • doubei5114 2013-08-20 16:05
    关注

    check your $row['id'] if it's returning something.

    <?php echo $row['id']; ?>
    

    or check your source code. your code might look something like

    <script type="text/javascript">
      function showDiv() {
        var note = "";
        document.getElementById("").style.display = "inline";
      }
    </script>
    
    评论

报告相同问题?

悬赏问题

  • ¥15 Vue3 大型图片数据拖动排序
  • ¥15 划分vlan后不通了
  • ¥15 GDI处理通道视频时总是带有白色锯齿
  • ¥20 用雷电模拟器安装百达屋apk一直闪退
  • ¥15 算能科技20240506咨询(拒绝大模型回答)
  • ¥15 自适应 AR 模型 参数估计Matlab程序
  • ¥100 角动量包络面如何用MATLAB绘制
  • ¥15 merge函数占用内存过大
  • ¥15 使用EMD去噪处理RML2016数据集时候的原理
  • ¥15 神经网络预测均方误差很小 但是图像上看着差别太大