douchuang8359 2014-05-12 12:54
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Php数组 - 无法从数组中获取值[关闭]

$data = '{"name":"CocaCola","price":1,"sync":0,"id":10792}';
$data = json_decode($data);

print_r((array)$data);
//Array ( [name] => CocaCola [price] => 1 [sync] => 0 [id] => 10792 )

print_r((array)$data["id"]);
//nothing?

This piece of code is not logic for me. Can I get any explanation of this behaviour and how to fix it?

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4条回答 默认 最新

  • duanqin9631 2014-05-12 12:57
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    (array)$data["id"]
    

    This is executed as

    (array)($data["id"])
    

    I.e. the result of $data['id'] is cast to an array; not $data cast to an array and then its id index accessed.

    If you want an array, use json_decode(..., true). Otherwise work with objects as objects instead of casting them to arrays all the time over and over.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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