删除如果_之前存在所有字符

Question

function categoriesIdsFunction($ids){
    //I try with preg_replace remove if exists all character before _
    $ids = preg_replace('/^[^_]*_\s*/', '', $ids);

    $ids = preg_replace('/\s+/', '', $ids);
      return "in ('" . str_replace(",","','",$ids) . "') ";
}

$categories_in_article = "267,267_463,267_462";

$categories_in_article_return = categoriesIdsFunction($categories_in_article);

With my code I take this: in ('463','267_462'), I try with preg_replace remove if exists all character before _ ($ids = preg_replace('/^[^]*\s*/', '', $ids);)

I need this return: in ('267','463','462')

Answer 1

I can't get what you need to return. If you need an array, you can try this:

$result = array_map(function (string $item) {
    return preg_replace('.+_', '', $item);
}, explode(',', $categoriesInArticle));

also, you can implode(',', $result) to get string w/o _ sign.