数组排序菜单

Question

I have the following array to show menu's based on the order the user specified.

The array is as follows:

$menuArray = [
    'Main Street' => [
        ['/index.php', 'Home'],
        ['/city.php', $cityData[$user->city][0]],
        ['/travel.php', 'Travel'],
        ['/bank.php', 'Bank'],
        ['/inventory.php', 'Inventory'],
        ['/dailies.php', 'Dailies'],
    ],
    'Activities' => [
        (!$my->hospital) ? ['/hospital.php', 'Hospital'] : [],
        (!$my->hospital && !$my->prison) ? ['/crime.php', 'Crime'] : [],
        ['/missions.php', 'Missions'],
        ['/achievements.php', 'Achievements'],
    ],
    'Services' => [
        ['/hospital.php', 'Hospital'],
        ['/prison.php', 'Prison'],
        ['/search.php', 'Search'],
    ],
    'Account' => [
        ['/edit_account.php', 'Edit Account'],
        ['/notepad.php', 'Notepad'],
        ['/logout.php', 'Logout'],
    ]
];

I have a column menu_order stored in the database, which has a default value of 0,1,2,3,4, but this can change per user as they will be able to change their menu to their likes.

What I'd like to achieve:

0 => Main Street
1 => Activities
2 => Services
3 => Account
4 => Communication

To get the menu order, I do

$menuOrder = explode(',', $user->menu_order);

But I'm not sure how to handle the foreach for displaying the menu.

Answer 1

You could try something like this to produce the menu:

function display_menu($menus, $m) {
    if (!isset($menus[$m])) return;
    echo "<ul>";
    foreach ($menus[$m] as $item) {
        if (!count($item)) continue;
        echo "<li><a href=\"{$item[0]}\">{$item[1]}</a>
";
    }
    echo "</ul>";
}
$menuMap = array(0 => 'Main Street',
1 => 'Activities',
2 => 'Services',
3 => 'Account',
4 => 'Communication');
$menuOrder = explode(',', $user->menu_order);
foreach ($menuOrder as $menuIndex) {
    $thisMenu = $menuMap[$menuIndex];
    display_menu($menuArray, $thisMenu);
}

Small demo on 3v4l.org