dox90448 2018-10-02 21:53
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PHP - 数组shenanigans

Currently, the code below only returns the first letter of the strings in $pizzas[]:

$total = 0;
  $pizzas = array('kebabpizza' => 80, 'calzone' => 60, 'vesuvio' => 60);
  foreach ($pizzas as $pizza => $price) {
    for($i = 0; $i < count($pizza); $i ++) {
      echo $pizza[$i] . " - $price<br>";
      break;
    }
    $total +=$price;
  }
  echo "Your order is gonna cost you $total kr<hr>";

Output:

k - 80
c - 60
v - 60
Your order is gonna cost you 200 kr
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5条回答 默认 最新

  • duangu1878 2018-10-02 22:01
    关注

    When you do your foreach loop, you're iterating over your array. When you say as $pizza => $price, the variable $pizza is assigned the key of the current array item you're looking at and $price is assigned the value. So in the first iteration of the loop $pizza is kebabpizza and $price is 80.

    Next, you're doing a for loop over the string kebabpizza (or whatever the key of the array is at that time). When you try to access $pizza[$i] in the first iteration of the for loop you're getting the letter k in kebabpizza. You're then echoing out k and then the price of the pizza.

    Following that you have a break statement which will terminate the inner for loop and the outer foreach loop will continue. That's why you're seeing only the first letters.

    Assuming you want to output the name of the pizza and the price, then you don't need the inner for loop at all:

    $total = 0;
    $pizzas = array('kebabpizza' => 80, 'calzone' => 60, 'vesuvio' => 60);
    foreach ($pizzas as $pizza => $price) {
        echo "$pizza - $price<br>";
    
        $total +=$price;
    }
    
    echo "Your order is gonna cost you $total kr<hr>";
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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