获取扩展类的文件名

Question

Let's say I have two files, each one has a class. How can I get the filename where the child class is, within the parent class?

File 2 (child class):

class B extends A{

}

File 1:

class A{

  final protected function __construct(){
    // here I want to get the filename where class B is, 
    // or whatever class is the child
  }

}

Answer 1

Not really sure what purpose it serves, but here you go:

class A{

  final protected function __construct(){
    $obj = new ReflectionClass($this);
    $filename = $obj->getFileName();
  }

}