Codeigniter从URL传递值

Question

Function receives departure date and adult from view page ( it passes value correctly as I have checked doing echo function ) , but from this function I am not able to pass values to another function

public function index()
{

    if ($data = $this->input->post('muktinath')) {

        $date = $data['departure_on'];
        $adult = $data['adult'];

        $getNameValue = array(
            $date = 'departure_on',
            $adult = 'adult',
        );

        redirect('booking/muktinath/' . $getNameValue);
    }

    else{
        $this->load->view('index');
    }
}

This is the function which must receive the value

public function muktinath($getNameValue)
{
    echo $getNameValue; 

    // here value must be shown of departure date and adult passed from above

}

Answer 1

You didn't share the error messages you are getting. Bet there several.

The biggest issue is you cannot put an array as a part of your query string. But the fix is pretty easy.

function index()
{
    $data = $this->input->post('muktinath'); 
    if($data)
    {
        //From your question $data seems to be an array already. Just use that!
        redirect('booking/muktinath/'.$data['departure_on'].'/'.$data['adult']);
    }
    else
    {
        $this->load->view('index');
    }
}

Your function that receives the values is then defined this way.

public function muktinath($date, $name)
{
    echo $date . " - " . $name;
}

You will have a problem if $date contains any slashes (/) in what I assume is a date string. The slashes will become part of the URL which, if the date was "7/9/2016" and name was "sandesh" would make this URL.

http://example.com/booking/muktinath/7/9/2016/sandesh

As you can see, it has several more URI segments than you are expecting. This URL would echo "7 - 9" which is not very helpful. You might have to adjust the format of the date while sending it and then reformat it after it is received by muktinath().

By the way, your array declaration is wrong. I think you were trying to make this.

$getNameValue = array(
   'departure_on' => $date,
   'adult' => $adult
   );

The thing is, you have just recreated what $data already was. But you don't need $getNameValue anyway.