dongyou6909 2013-11-13 10:30
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Php - 按天记录的组记录

I have a following table:

  CREATE TABLE IF NOT EXISTS "visits" ( 
  "id" int(10) unsigned NOT NULL AUTO_INCREMENT,
  "start" datetime NOT NULL,
  "finish" datetime NOT NULL,
  "name" varchar(50) NOT NULL,
  PRIMARY KEY ("id")
)

And I would like to display visits for next 2 days as shown in the following code:

<div id="day>Today</div>
<a href="#">VISIT NAME</a>
<a href="#">VISIT NAME</a>
<a href="#">VISIT NAME</a>
<div id="day>Tomorrow</div>
<a href="#">VISIT NAME</a>
<a href="#">VISIT NAME</a>
<div id="day>15-11-2013</div>
<a href="#">VISIT NAME</a>

At this moment I have only this I'm looking for PHP code :) At this moment I have only:

$link=mysql_query('select count(*), DATE_FORMAT(start,"%Y-%m-%d") as start FROM visits GROUP BY start');
            while($row=mysql_fetch_array($link))
            {
            echo'<div id="day">'.$row['start'].' '.$row['count(*)'].'</div>';
            }

but that show only

<div id="day>Today 3</div>
<div id="day>Tomorrow 2</div> 
<div id="day>15-11-2013 1</div>

Thanks in advance for your help.

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1条回答 默认 最新

  • doujia7094 2013-11-13 10:48
    关注

    Try this.

    $sql = "
        SELECT *, DATE(`start`) AS group_name
        FROM `visits`
        WHERE DATE(`start`) BETWEEN CURDATE() AND CURDATE() + INTERVAL 2 DAY
        ORDER BY `start` ASC
    ";
    $result = mysql_query($sql) or die(mysql_error());
    $group = null;
    while ($row = mysql_fetch_assoc($result)) {
        if (is_null($group) || $group != $row['group_name']) {
            $group = $row['group_name'];
            echo '<div id="day">' . $row['group_name'] . '</div>';
        }
        echo '<a href="#">' . $row['name'] . '</a>';
    }
    
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