dongxianshuai8927 2015-01-16 08:12
浏览 29

如何使我的PHP滑块工作

My php slider is sort of working i have managed to get it to link to my database. However, i need it to loop through all the images within my slider and my code isn't work but i believe i have missed a loop query?!

THIS IS MY CODE WHERE MY SLIDER IS:

<div class="theme-dark 16 columns">
        <div id="slider" class="nivoSlider">

            <img src="<?php print $row['image']?>"/>
           <!--  <img src="images/nivo/arts.png" alt="the grand theatre and nothern ballet">
            <img src="images/nivo/slider3.png" alt="leeds night light slider image">
            <img src="images/nivo/slider2.png" alt="Leeds Trinity slider image">
            <img src="images/nivo/slider4.png" alt="leeds art hotels">
            <img src="images/nivo/slider1.png" alt="leeds art slider image"> -->
        </div>
</div>

THIS IS MY CODE TO RUN MY SLIDER AT THE MOMENT:

<?php

$myQuery = "SELECT * FROM SliderImg";

$result = $con->query($myQuery);
if (!$result) die('Query error: ' . mysqli_error($con));


$row = mysqli_fetch_array($result);
?>
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3条回答 默认 最新

  • drzrdc1766788 2015-01-16 08:19
    关注

    you need a loop in your php:

    <?php
    $myQuery = "SELECT * FROM SliderImg";
    
    $result = $con->query($myQuery);
    if (!$result) die('Query error: ' . mysqli_error($con));
    
    $rows = array();
    
    while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) {
        $rows[] = array(
            'image' => $row['image'];
        )
    }
    ?>
    

    And in your HTML:

    <div class="theme-dark 16 columns">
        <div id="slider" class="nivoSlider">
            <?php 
            foreach($rows as $row) { ?>
                <img src="<?php print $row['image']?>"/>
            <?php 
            } ?>
        </div>
    </div>
    
    评论

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