如何使用php发送javascript制作的滑块中的值

Question

I use the jquery code made a slider in my website and i want to sent the value I get from the slider to my database with php. The jquery code sites address is right here. http://jqueryui.com/slider/#steps

My html form code:

<form action="like.php" method="post" id = "button">
<input type="hidden" name="likefemale" value = "<?php echo $rand_num_rows;?>"/>
<input type="hidden" name="likemale" value = "<?php echo $rand_num_rows1;?>"/>
<input type = "hidden" name = "slider_val" id = "slider_val"/>
<input name="like" type="submit" value="like" />
</form>

<form action="unlike.php" method="post" id = "button1">
<input type="hidden" name="unlikefemale" value = "<?php echo $rand_num_rows; ?>"/>
<input type="hidden" name="unlikemale" value = "<?php echo $rand_num_rows1; ?>"/>
<input type = "hidden" name = "slider_val" id = "slider_val"/>
<input name="unlike" type="submit" value="unlike" />
</form>

I want the value sent by this two forms.

Answer 1

On your jqueryUI slider code, use slide event to get it's value. For example:

$("#yourSlider_1").slider({
    [...]
    slide: function( event, ui ) {
        $( "#slider_val_1" ).val( ui.value );
    }
});

Also, use a different ID for the hidden inputs "slider_val" of your forms.