PHP如果$ var null则返回$ var2

Question

I havent been able to find an answer to this:

My code works like this:

echo ' <p> '.$test2.'</p> ';

I want to make $test2 change if it is null i have tried the following code and bunch of other and it just breaks the page

$test2 = if(empty($price)){ return $pstatus};

Any help would be apprteciated

UPDATE I have modified my code, now it returns the price but if the price is empty its returning nothing when it should return the $pstatus

so $price is say 625000 is that variable is empty it should return sold from the $pstatus variable

$price = number_format($p->meta_box->REAL_HOMES_property_price);
$fimage = $p->better_featured_image->media_details->sizes->medium->source_url;
$ptitle = $p->title->rendered;
$pdesc = $p->excerpt->rendered;
$plink = $p->link;
$pstatus = $p->pure_taxonomies->{"property-status"}[0]->name;
$test2 = $pstatus ? $price : $test2;

Answer 1

You can do it inline:

$test2 = $price ? $pstatus : $test2;

If you need to assign "$price" to "$test2" and if there is no price then assign "$pstatus":

$test2 = $price ? $price : $pstatus;