具有多个单词的数组搜索

Question

I have an array like that:

(
(0) => Array
    (
        (uid) => '100',
        (name) => 'Blue t-shirt 4 years',
        (ean) => '123456'
    ),

(1) => Array
    (
        (uid) => '5465',
        (name) => 'blue shirt 24 years',
        (ean) => '123'
    ),

(2) => Array
    (
        (uid) => '40489',
        (name) => 'Shirt 4 Years',
        (ean) => '12345'
    )
);

I am trying to count how many entries in the array have all the words on the key name "shirt 4 years" case insensitive or have the same 'ean' number.

In that case would return 2. What's the best way to do that?

Answer 1

You can prepare regex that matches provided words in any order:

function words_regex(array $words) {
    $regex = array_reduce($words, function($carry, $word) {
        return $carry . '(?=.*\b' .  preg_quote($word) . '\b)';
    }, '/');

    return $regex . '.*/i';
}

Having this function you can filter items and count them:

$regex = words_regex($words);

$count = count(array_filter($array, function($item) use ($regex) {
    return preg_match($regex, $item['name']);
}));

Here is working demo.