du958642589
2018-03-13 13:29
浏览 106

在完成函数jquery上重新加载表单

I want to pass an input value to a php session variable. With the code below, I can send the input value to the session but only appears in the alert box or if I refresh the page, which I do not want. I added the line $ ("# form1") [0] .reset (); to refresh the form and thus have the value of the session printed on the screen, but it is not working.

index.php:

<?php
    @session_start();
    error_reporting(0);
    ?>
  <!doctype html>
  <html>

  <head>
    <meta charset="utf-8">
    <title>input value to php session</title>
    <script src="https://ajax.googleapis.com/ajax/libs/jquery/3.2.1/jquery.min.js"></script>
  </head>

  <body>
    <form method="post" id="form1">
      <input type="text" name="field1" id="field1" onblur="run(this)">
    </form>
    <br /><br />
    <?php echo $_SESSION['field1'];?>
    <script src="https://ajax.googleapis.com/ajax/libs/jquery/3.2.1/jquery.min.js"></script>
    <script language="javascript">
      function run(sel) {
        var text = $("#field1").val();
        if (text != "") {
          $.ajax({
            type: "POST",
            url: "input.php",
            data: {
              field1: text
            }
          }); //.done(function() {alert(text)});    
        }

        if (done.(function() {
            $("#form1").reset()
          }));
      }
    </script>
  </body>

  </html>

The input.php file:

<?php
  @session_start();
  error_reporting(0);

  if (isset($_POST["field1"])){
    $_SESSION['field1'] = $_POST["field1"]; 
  }
?>
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3条回答 默认 最新

  • dpr77335 2018-03-13 13:45
    已采纳

    You could create a <div> around your value and change it when .done():

    To get your session value, you have to echo it and use it inside your done() callback:

    <?php
    @session_start();
    error_reporting(0);
    ?>
    <!doctype html>
    <html>
    <head>
    <meta charset="utf-8">
    <title>input value to php session</title>
    </head>
    <body>
    <form method="post" id="form1">
    <input type="text" name="field1" id="field1" onblur="run(this)">
    </form>
    <br /><br />
    
    <!-- HERE wrap into a div with an ID -->
    <div id="session-field"><?php echo $_SESSION['field1'];?></div>
    
    
    <script src="https://ajax.googleapis.com/ajax/libs/jquery/3.2.1/jquery.min.js"></script>
    <script language="javascript">
    function run(sel) {
        var text = $("#field1").val();
        if (text != "") {
            $.ajax({
                type: "POST",
                url: "input.php",
                data: { field1: text}
            })
            // done callback using data (wha
            .done(function(data) {
                $('#session-field').html(data);
                $("#field1")[0].form.reset();
            });
        }
    }
    </script>
    </body>
    </html>
    

    And your input.php:

    <?php
    @session_start();
    error_reporting(0);
    
    if(isset($_POST["field1"])){
       $_SESSION['field1'] = $_POST["field1"];
       echo $_SESSION['field1'] ; // echo outputs
    }
    ?>
    
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  • dongshou1856 2018-03-13 13:46

    If you are trying to simply display the value that was just sent to PHP, you can do it in a couple of ways.

    First, you could just put in on the page with JS

    function run(sel) {
            var text = $("#field1").val();
            $('#some_div').append(text);
            if (text != "") {
              $.ajax({
                type: "POST",
                url: "input.php",
                data: {
                  field1: text
                }
              }); 
            }
    

    Or if you want to be sure it was saved as the SESSION variable, you can return it from PHP and then put it on the page with JS

    <?php
      @session_start();
      error_reporting(0);
    
      if (isset($_POST["field1"])){
        $_SESSION['field1'] = $_POST["field1"]; 
        echo $_SESSION['field1'];
      }
    
    ?>
    

    and then in your JS

    function run(sel) {
           var text = $("#field1").val();
           $('#some_div').append(text);
           if (text != "") {
             $.ajax({
                type: "POST",
                url: "input.php",
                data: {
                  field1: text
                },
                success: function(data) {
                    $('#some_div').append(data);
                }
              }); 
            }
    
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  • douan3414 2018-03-13 13:46

    Just add a div to your HTML with id output-session and then print the $_POST["field1"] in input.php so it get's appended to that div.

    index.php

    <script language="javascript">
    function run(sel) {
    var text = $("#field1").val();
    if (text != "") {
        $.ajax({
            type: "POST",
            url: "input.php",
            data: { field1: text},
            success: function(msg){
    
              if (msg != ''){                
              $("#output-session").html(msg);
              }        
            }
        });
    }
    </script>
    <div id="output-session"></div>
    

    input.php

    <?php
    @session_start();
    error_reporting(0);
    
    if(isset($_POST["field1"])){
    $_SESSION['field1'] = $_POST["field1"]; 
    print $_POST["field1"];
    }
    ?>
    
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