doulao3905 2013-10-25 15:21
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调用未定义的函数logged_in()

I have a function logged_in() whose purpose is to check if the user is logged in. This function, located inside users.php, is called from login.php.

Everytime I attempt to call this function I get the following error

Call to undefined function logged_in() in line 67

Here's my code

users.php

function logged_in() //line 67 
{
    return (isset($_SESSION['user_id'])) ? true : false;
}

login.php

if(logged_in()===true)
{
    include 'includes/widgets/loggedin.php';
}
else{
    include 'includes/widgets/login.php';
}

What seems to be the issue?

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3条回答 默认 最新

  • douang4294 2013-10-25 15:22
    关注

    Looks like you forgot to include users.php. If you don't include that file you don't have access to any functions declared within it.:

    <?php 
    include('users.php');
    if(logged_in()===true)
    {
        include 'includes/widgets/loggedin.php';
    }
    else{
            include 'includes/widgets/login.php';
    }
    
    ?>
    
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