获取日期返回零之间的差异

Question

I have a date time in 'Y-m-d H:i:s', and i tried to substract the now date with the defined date +1 day to get remaining time in hours, minutes and seconds:

$time = '2017-10-05 14:54:03';
$now =  date('Y-m-d H:i:s');
$endTransaction = date('Y-m-d H:i:s', strtotime($time. ' + 1 day'));
$dteDiff  = $endTransaction - $now;
echo $dteDiff;

but i always get 0 as the result

Answer 1

You are doing it wrong. The date function returns string so PHP is not able to compare anything. Try with the DateTime class instead. Its diff method returns the DateInterval object with some public properties, like the days property among others, which is the positive integer number (rounded down) of days between two dates:

$now = new \DateTime();
$endTransaction = (new \DateTime('2017-12-05 14:54:03'))->modify('+1 day');

$diff = $endTransaction->diff($now);

printf(
    'Difference in days: %d, hours: %d, minutes: %d, seconds: %d',
     $diff->days,
     $diff->h,
     $diff->m,
     $diff->s
);