查询wongt输出到表。 正确的语法

Question

What am i doing wrong here? (Know its mysql) this else is not working it look like. user can insert same modul id many times.

$besvarelse = $_GET['besvarelse'];
$modulid = $_GET['modulid'];
$username = $_GET['username'];

$tilkobling = kobleTil(); 
if (!empty($besvarelse) ) {
      $insert = mysql_query("INSERT INTO oppgave (besvarelse, modulid, username) VALUES ('$besvarelse', '$modulid','$username')");


if($insert) {

          echo "<h1>Levering OK</h1><br>";

        }
    }
    else {

        die("<h1>Du har lever før</h1>");

    }
?>

Answer 1

Try with this and post the errors that PHP shows, please:

//Assuming that connection to mysql server its done somewhere with mysql_connect()

error_reporting(E_ALL); ini_set('display_errors', 1);
explode($_GET);

echo "<pre>";
print_r($_GET); //Just to see what's on the variables...
echo "</pre>;

// $tilkobling = kobleTil(); Need to explain this line

if (!empty($besvarelse) ) {
$sql = "INSERT INTO oppgave (besvarelse, modulid, username) VALUES ('$besvarelse', '$modulid','$username')";

if($insert = mysql_query($sql))
       {
          echo "<h1>Levering OK</h1><br>";

        }

    else {

        die("<h1>Du har lever før</h1>");

    }
} // you were missmatching the IF closing bracket

?>