doufeixi6014 2012-10-04 02:25
浏览 70
已采纳

PHP拆分数组作为参数传递[重复]

Possible Duplicate:
How to pass a variable number of parameters to a function in PHP

I'm trying to dynamically populate parameters when calling a method based on get requests.

For example:

Let's say I have an array with four values:

array(1, 2, 3, 4);

Now I want to pass this to a method that accepts these four parameters. However, this needs to be dynamic, so I can't just do for example method($array[0], array[1], array[2], array[3]).

My question is, how can I take an array with variable lengths and pass it to methods that may also accept varying parameters?

Thank you!

  • 写回答

1条回答 默认 最新

  • duanshang7007 2012-10-04 02:31
    关注

    You can use call_user_func_array

    function method($arg1, $arg2, $arg3, $arg4){
        echo "$arg1, $arg2, $arg3, $arg4";
    }
    call_user_func_array(method, array(1, 2, 3, 4));//prints 1, 2, 3, 4
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

报告相同问题?

悬赏问题

  • ¥15 关于#MATLAB#的问题,如何解决?(相关搜索:信噪比,系统容量)
  • ¥500 52810做蓝牙接受端
  • ¥15 基于PLC的三轴机械手程序
  • ¥15 多址通信方式的抗噪声性能和系统容量对比
  • ¥15 winform的chart曲线生成时有凸起
  • ¥15 msix packaging tool打包问题
  • ¥15 finalshell节点的搭建代码和那个端口代码教程
  • ¥15 Centos / PETSc / PETGEM
  • ¥15 centos7.9 IPv6端口telnet和端口监控问题
  • ¥20 完全没有学习过GAN,看了CSDN的一篇文章,里面有代码但是完全不知道如何操作