dpzyd8865 2019-04-13 16:35
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SQL数组var_dump什么都没显示

I have some code for load business-hours. My databas looks like

id - int(11)
day - varchar(255)
starttime - (time)
endtime - (time)
date - (date)
type - int(1)

I try to get the data with:

if ($conn->connect_error) {
    die("Connection failed: " . $conn->connect_error);
} 
echo "Connected successfully";

function get_all_records($sql){
    global $conn;

    $result = $conn->query($sql);
    $result = [];
    while($row = $result->fetch_assoc()) $result[array_shift($row)] = $row;
    return $result;
}

$sql = "SELECT day, starttime, endtime FROM schedule WHERE type =  ";

$shop_hours = array_merge(
    get_all_records($sql . "0 ORDER BY id"),
    get_all_records($sql . "1 and YEARWEEK('DATE') = '201915'")
);


var_dump ($shop_hours);
?>

Only what is displayed is Connected successfully

I can't see the issue :(

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2条回答 默认 最新

  • douxuan1284 2019-04-13 17:12
    关注

    I found the issue on line 14

    while($row = $query->fetch_assoc()) $result[array_shift($row)] = $row;

        <?php    
    $conn = new mysqli($dbhost, $dbusername, $dbpassword, $dbname);
    
    if ($conn->connect_error) {
        die("Connection failed: " . $conn->connect_error);
    } 
    echo "Connected successfully";
    
    function get_all_records($sql){
      global $conn;
    
      $query = $conn->query($sql);
      $result = [];
      while($row = $query->fetch_assoc()) $result[array_shift($row)] = $row;
      return $result;
    }
    
    $sql = "SELECT day, starttime, endtime FROM schedule WHERE type = ";
    $shop_hours = array_merge(
      get_all_records($sql . "0 ORDER BY id"),
      get_all_records($sql . "1 and YEARWEEK('DATE') = '201915'")
    );
    
    var_dump($shop_hours);
    ?>
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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