March of the Penguins 的解决办法

Question

Problem Description
Somewhere near the south pole, a number of penguins are standing on a number of ice floes. Being social animals, the penguins would like to get together, all on the same floe. The penguins do not want to get wet, so they have use their limited jump distance to get together by jumping from piece to piece. However, temperatures have been high lately, and the floes are showing cracks, and they get damaged further by the force needed to jump to another floe. Fortunately the penguins are real experts on cracking ice floes, and know exactly how many times a penguin can jump off each floe before it disintegrates and disappears. Landing on an ice floe does not damage it. You have to help the penguins find all floes where they can meet.

A sample layout of ice floes with 3 penguins on them.

Input
On the first line one positive number: the number of testcases, at most 100. After that per testcase:

One line with the integer N (1 ≤ N ≤ 100) and a floating-point number D (0 ≤ D ≤ 100 000), denoting the number of ice pieces and the maximum distance a penguin can jump.

N lines, each line containing xi, yi, ni and mi, denoting for each ice piece its X and Y coordinate, the number of penguins on it and the maximum number of times a penguin can jump off this piece before it disappears (−10 000 ≤ xi, yi ≤ 10 000, 0 ≤ ni ≤ 10, 1 ≤ mi ≤ 200).

Output
Per testcase:

One line containing a space-separated list of 0-based indices of the pieces on which all penguins can meet. If no such piece exists, output a line with the single number −1.

Sample Input
2
5 3.5
1 1 1 1
2 3 0 1
3 5 1 1
5 1 1 1
5 4 0 1
3 1.1
-1 0 5 10
0 0 3 9
2 0 1 1

Sample Output
1 2 4
-1

Answer 1

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# 导入必要的库
library(Rcpp)
library(Rcpp::Rcpp)

# 定义函数
jump_distance <- function(x, y, d) {
  return(sqrt((x - y)^2 + d^2))
}

# 定义主函数
solve_penguins <- function(testcase_count) {
  # 初始化结果向量
  result <- rep(-1, testcase_count)
  
  # 遍历测试数据集
  for (i in 1:testcase_count) {
    # 获取当前测试数据的参数
    n <- readLines()[[i]][1]
    d <- as.numeric(readLines()[i][2])
    
    # 初始化penguins数组和ice_floes数组
    penguins <- matrix(NA, nrow = 1, ncol = 4)
    ice_floes <- matrix(NA, nrow = 1, ncol = 6)
    
    # 将冰块信息写入矩阵中
    for (j in 1:n) {
      x <- as.numeric(readLines()[i + j * n])
      y <- as.numeric(readLines()[i + j * n + 1])
      n_i <- as.integer(readLines()[i + j * n + 2])
      m_i <- as.integer(readLines()[i + j * n + 3])
      
      # 将冰块的信息添加到penguins和ice_floes矩阵中
      penguins[, c("X", "Y")] <- c(x, y)
      penguins[, c("ni", "mi")] <- c(n_i, m_i)
      
      # 计算每个冰块可以跳的距离
      for (k in 1:m_i) {
        ice_floes[j, k] <- jump_distance(penguins[k, 1], penguins[k, 2], d)
      }
    }
    
    # 对于每个冰块，检查它是否可以被所有penguins跳过
    for (j in 1:nrow(ice_floes)) {
      is_valid <- TRUE
      for (k in 1:ncol(ice_floes)) {
        if (ice_floes[j, k] <= 0 || ice_floes[j, k] > n_i) {
          is_valid <- FALSE
          break
        }
      }
      
      if (is_valid) {
        # 如果所有冰块都满足条件，输出当前测试数据的index
        result[i] <- j
      } else {
        # 如果没有满足条件的冰块，输出-1
        result[i] <- -1
      }
    }
  }
  
  # 返回结果向量
  return(result)
}

# 调用主函数并获取结果
result <- solve_penguins(1L)
print(result)

请注意，上述代码使用了Rcpp库来实现C++风格的编程。在实际应用中，请确保已经安装了Rcpp包，并且正确配置环境变量以访问其中的函数。