PHP列表目录递归发布

Question

I'm trying to list all PHP files in a specified directory and for it to recursively check all sub-directories until it finds no more, there could be numerous levels.

The function I have below works fine with the exception that it only recurses down one level.

I've spent hours trying to see where I'm going wrong, I'm calling the scanFiles() when it finds a new directory but this only seems to work one level down and stop, any help greatly appreciated.

Updated:

function scanFiles($pParentDirectory)
{
    $vFileArray = scandir($pParentDirectory);
    $vDirectories = array();

    foreach ($vFileArray as $vKey => $vValue)
    {
        if (!in_array($vValue, array('.', '..')) && (strpos($vValue, '.php') || is_dir($vValue)))
        {
            if (!is_dir($vValue))
                $vDirectories[] = $vValue;
            else
            {
                $vDirectory = $vValue;
                $vSubFiles = scanFiles($vDirectory);
                foreach ($vSubFiles as $vKey => $vValue)
                        $vDirectories[] = $vDirectory.DIRECTORY_SEPARATOR.$vValue;
            }
        }
    }

    return $vDirectories;
}

Answer 1

You can do this easily like this:

// helper function
function getFiles(&$files, $dir) {
    $items = glob($dir . "/*");
    foreach ($items as $item) {
         if (is_dir($item)) {
            getFiles($files, $item);
        } else {
            if (end(explode('.', $item)) == 'php') {
                $files[] = basename($item);
            }
        }
    }
}

// usage
$files = array();
getFiles($files, "myDir");

// debug
var_dump($files);

myDir looks like this: has php files in all dirs

Output:

---

P.S. if you want the function to return the full path to the found .php files, remove the basename() from this line:

$files[] = basename($item);

This will then produce result like this:

hope this helps.