dongyi5817 2015-08-07 16:13
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preg_replace一个带有h5标签的特定字符串

I want to do the following using preg_replace:

$text = "
Lorem ipsum dolor sit amet
***consectetuer adipiscing elit
Aenean commodo ligula eget dolor
Aenean massa
"

$regex = "#('\***')(.*?)
#";
$text = preg_replace($regex1,"<h5>$2</h5>", $text);

And than the output:

Lorem ipsum dolor sit amet
<h5>consectetuer adipiscing elit</h5>
Aenean commodo ligula eget dolor
Aenean massa

So replace the three * with an opening H5 and than the first line break after the three * replace with the closing H5.

I tried many regex patterns, but with no success. As I'm not familiar with this I hope someone can help me?

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  • duanpai1033 2015-08-07 16:18
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    Your regex was on the right track.

    • The single quotes are uneeded:

      $regex = "#('\***')(.*?)
      #";
                  ↑    ↑
      
    • And each literal * needs escaping:

      $regex = "#(\*\*\*)(.*?)
      #";
      

    I would also match the right in the second capture group, or use \R for any linebreak. Or perhaps even the #m flag and just the line end $ anchor.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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