duangou1953 2013-10-10 18:59
浏览 28
已采纳

在函数内部加载视图不起作用

I got some weird error (CodeIgniter) :

Call to undefined function view().

However I am using login as default controller. index() is loading the page perfectly while loading the view in the function doesn't work.

 <?php if ( ! defined('BASEPATH')) exit('No direct script access allowed');


 class Login extends CI_Controller{



public function index(){
    $this->load->view('login_view');
}

public function processLogin(){
    if(isset($_POST['username']) && isset($_POST['password'])){
        if(!empty($_POST['username']) && !empty($_POST['password'])){
            $this->load->model("user");
            $suc = $this->user->login($_POST['username'],$_POST['password']);

            if($suc !=0 && $suc !=-1){

            }
            else{
                if($suc == 0){
                    $data['error'] = "Invalid credentials";
                    $this->load>view('login_view',$data);
                }
                else{
                    $data['error'] = "Multiple user exist with same logon";
                    $this->load>view('login_view',$data);
                }


            }

        }
    }
}



}

?>
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1条回答 默认 最新

  • dsgwoh7038 2013-10-10 19:02
    关注

    You have miss a - near >

    change this:

     if($suc == 0){
                        $data['error'] = "Invalid credentials";
                        $this->load>view('login_view',$data);
                    }
                    else{
                        $data['error'] = "Multiple user exist with same logon";
                        $this->load>view('login_view',$data);
                    }
    

    to this:

    if($suc == 0){
                    $data['error'] = "Invalid credentials";
                    $this->load->view('login_view',$data);
                }
                else{
                    $data['error'] = "Multiple user exist with same logon";
                    $this->load->view('login_view',$data);
                }
    

    I have change in two lines this: $this->load>view to this: $this->load->view

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

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