dreljie602951 2014-04-10 14:46
浏览 87

mysql_fetch_array将值拉入变量

I know that this is dozy, but getting to the end of my tether, this should work, but I can't see why I can't place the first value of my order table into the variable order_id, can anyone see my mistake?

Thanks

$con = mysql_connect("localhost", "tim", "password");

if (!$con) {
    die('Could not connect: '.mysql_error());
}

$sql = "SELECT TOP 1 order_order_id FROM tbl_order ORDER BY order_id DESC";
$result = mysql_query($sql, $con);

while ($rows = mysql_fetch_array($result)) {
    $order_id = $rows;
}
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1条回答 默认 最新

  • dongsi7759 2014-04-10 14:55
    关注

    Use this code and let me know if it works:

    $con = mysql_connect("localhost","tim","password");
    
    if (!$con)
       {
       die('Could not connect: ' . mysql_error());
      }
    $sql = "SELECT TOP 1 order_order_id FROM tbl_order ORDER BY order_id DESC";
    $result = mysql_query($sql,$con);
    if (mysql_num_rows($result)) {
         $rows = mysql_fetch_assoc($result);    
         $order_id = $rows['order_order_id'];    
    } else {
         die('No order ID found');
    }
    
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