dongnaopa6200
dongnaopa6200
2015-07-23 09:26
浏览 35
已采纳

删除php中子字符串中不需要的空格?

I've Scenario where user type a string in search box. If the entered string reaches more than one word, i explode it by using,

$text = "Hello World";
$pieces = explode(' ', $text);

and i will get the first and second term by

$pieces['0'] & $pieces['1'].

But, if an user type something like,

$text = "Hello                    World";

how should i get the second term?

If i var_dump the results, i'm getting

array(12) {
  [0]=>
  string(5) "Hello"
  [1]=>
  string(0) ""
  [2]=>
  string(0) ""
  [3]=>
  string(0) ""
  [4]=>
  string(0) ""
  [5]=>
  string(0) ""
  [6]=>
  string(0) ""
  [7]=>
  string(0) ""
  [8]=>
  string(0) ""
  [9]=>
  string(0) ""
  [10]=>
  string(0) ""
  [11]=>
  string(5) "World"
}
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4条回答 默认 最新

  • douyan4958
    douyan4958 2015-07-23 09:28
    已采纳

    Instead of explode() use preg_split() and then use \s+ (\s space, + 1 or more times) as delimiter. Like this:

    $pieces = preg_split("/\s+/", $text);
    
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  • dqusbxh44823
    dqusbxh44823 2015-07-23 09:29

    replace multiple spaces with single space by using this

    $output = preg_replace('!\s+!', ' ', $text);
    

    then split the text

    $pieces = explode(' ', $output);
    
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  • doulu3808
    doulu3808 2015-07-23 09:33

    Try:

    <?php
    $text = "Hello World";
    
    // BONUS: remove whitespace from beginning and end of string
    
    $text = trim($text);
    
    // replace all whitespace with single space
    
    $text = preg_replace('!\s+!', ' ', $text);
    $pieces = explode(' ', $text);
    ?>
    
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  • doumu4916
    doumu4916 2015-07-23 09:36

    Rizier123's answer is valid enough, but if you want to avoid using preg_split which uses regular expression checking, you could get your array with the empty strings and just remove all empty elements from it like so:

    $text = "Hello      World";
    $pieces = array_filter(explode(' ', $text));
    
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