duandui2803 2018-05-25 06:05
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在PHP中使用preg_Replace()函数时出现问题[重复]

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I have used the preg_Replace function in CorePHP as follows:

$d [] = preg_Replace("^0", "", $a);

But I'm getting the following error as:

Warning: preg_replace(): No ending delimiter '^'

What does the No ending delimiter mean? What am I missing here?

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  • dongqiang2024 2018-05-25 06:09
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    You need to slightly change your syntax to one of the following two options:

    $d[] = preg_replace("/^0/", "", $a);
    

    or

    $d[] = preg_replace("(^0)", "", $a);
    

    Demo

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